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9. Connessione: indipendenza assoluta /3

  • \(\displaystyle{\hat{n}_{11} = \frac{30\times 45}{100} =13,5} \)

  • \(\displaystyle{\hat{n}_{12} = \frac{30\times 30}{100} =9}\)

  • \(\displaystyle{\hat{n}_{13} = 30 - 13,5 - 9 = 7,5}\)

  • \(\dots\)


    Notare che i marginali restano invariati!
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