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33. Correlazione per caratteri qualitativi /6

 Numeratore

\[\begin{eqnarray}\nonumber &  & \sum_{k=1}^{n}{r_k\,s_k} - n\left( \frac{n+1}{2}  \right)^2\cr &=& \sum_{k=1}^{n}{r_k\,s_k} - 3n\left( \frac{n+1}{12}  \right)(n+1)\cr  &=& \sum_{k=1}^{n}{r_k\,s_k} + n\left( \frac{n+1}{12}  \right)(-3n - 3)\cr &=& \sum_{k=1}^{n}{r_k\,s_k} + n\left( \frac{n+1}{12}  \right)[(n-1) - (4n + 2)]\cr &=& \frac{n(n+1)(n-1)}{12} - \frac{(n+1)(2n + 1)}{6} + \sum_{k=1}^{n}{r_k\,s_k}\cr &=& \frac{n(n^2 - 1)}{12} - \frac{1}{2}\sum_{k=1}^{n}(r_k^2 + s_k^2) +  \sum_{k=1}^{n}{r_k\,s_k} \cr & \, & \color{brown}{ \boxed{ = \frac{n(n^2 - 1)}{12} - \frac{1}{2}\sum_{k=1}^{n}(r_k -  s_k)^2 } } \end{eqnarray} \] \[ \qquad \]

Digressioni

\[\bar{r} = \bar{s} = \displaystyle{\frac{n+1}{2}}\]\[\sum_{k=1}^{n} r_k = \sum_{k=1}^{n} s_k =  \displaystyle{\frac{n(n+1)}{2}}\]


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